-.005x^2+.35x=-3

Solution for -.005x^2+.35x=-3 equation:

-.005x^2+.35x=-3

We move all terms to the left:

-.005x^2+.35x-(-3)=0

We add all the numbers together, and all the variables

-0.005x^2+.35x+3=0

a = -0.005; b = .35; c = +3;
Δ = b2-4ac
Δ = .352-4·(-0.005)·3
Δ = 0.1825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.35)-\sqrt{0.1825}}{2*-0.005}=\frac{-0.35-\sqrt{0.1825}}{-0.01}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.35)+\sqrt{0.1825}}{2*-0.005}=\frac{-0.35+\sqrt{0.1825}}{-0.01}
$